Restate the question. Solve: x3 = 4x
(Algebra can be hard to write with a keyboard.)
x3 = 4x
x3/x = 4x/x {divide both sides by x}
x2 = 4*
x = plus or minus radical 2
x = +/- 2
*or you could go:
x2 - 4 = 0
(x - 2)(x+2) = 0
x - 2 = 0 or x + 2 = 0
x = 2 or x = -2
x = +/-2
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Answer 1:
3x = 4x
If you divide both sides by x, you get
3 = 4
So this approach doesn't seem to work. However, if you take all terms to the left side, you get:
3x - 4x = 0
-x = 0
Multiplying by (-1):
x = 0
So zero is the solution. The reason the first approach didn't work is because I was dividing by zero. If you do try this - and it makes sense, for more complicated equations - you have to separately analyze the possibility that x = 0.
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
IMPOSSIBLE
-12 (?)
-3
-4x-4 equals -16. Add 4 to both sides; -4x equals -12. Divide both sides by -4; x equals 3.
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
X(X2 - X)
IMPOSSIBLE
4x = 72.divide both sides by 4x = 18
-12 (?)
-3
2y = 4x + 4y = 2x + 2
X is 6
x = 5
-4x-4 equals -16. Add 4 to both sides; -4x equals -12. Divide both sides by -4; x equals 3.
4x = 16Divide each side of the equation by 4:x = 4
Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)