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What else can I help you with?
How to factorise X to the power of 5 - 4x squared?
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What is x3 equal 4x?
It is a cubic equation in the variable x.
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
How do you factorise x3 plus xy-x2y2?
x3+xy-x2y2=x(x2+y-xy2)
How do you factorise x3 - 27?
-24
How do you find the solutions of x3-12x plus 7?
Since that isn't an equation, there is really nothing to solve.
Find the factors of x3-5x2 8x-4 how to solve this equation?
5x2-8x-4
What are the zeros of the polynomial function fx equals x3-4x2-12x?
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
Y x3 4x - 3.6?
55846.2365
What I helps you to find the area under the curve y x3 4x 3.6?
well, it would help to clarify your question, but integrate the fuction and solve on the interval given
How do you factorise x4 plus x3-7x2 plus 6?
Another, simpler way of writing this would be: 4x + 3x - 7 x 2 + 6 To start, using order of operations, you would do 7 x 2 which equals 14. So now you've got 4x + 3x - 14 + 6. Because different terms are being used, we collect like terms. First is 4x + 3x which equals 7x. Then there's 14 + 6 BUT because before the 14 there is a minus sign, it becomes NEGATIVE 14. It should now look like -14 + 6 which equals -8. Now the entire equation should look like 7x - 8. I have simplified the equation, but you are in fact unable to factorise it because there are no common factors of 7 and 8.
