x^(3) +x^(2) - x = 0
Factor
x(x^(2) + x - 1) = 0
First part of the answerr is x = 0
Second part of the answer
x^(2) + x - 1 = 0
Use Quadratic Eq'n.
x = { -1 +/- sqrt[1^(2) - 4(1)(-1_]} / 2(1)
x = { -1 +/- sqrt[1 + 4]} / 2
x = ( -1 +/- sqrt)5)} / 2
x = =1 +/- 2.236...} / 2
x = -1/2 +/- 2.236.../2
X = -0.5 +/- 1.118...
x = - 1.618.... & x = 0.618....
So the three values of x that satisfy the equ'n are
x = 0 , -1.618.... & 0.618....
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
IMPOSSIBLE
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
No.
It is x = -5
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
IMPOSSIBLE
cube root of 216 = 6 > X= 6
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
No.
y2=x3+3x2
It is x = -5
No, it is not.
(xn+2-1)/(x2-1)
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Since that isn't an equation, there is really nothing to solve.