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x + y = 4 and y = 2x + 1
The first equation can be rearranged to show x = 4 - y (Effectively y has been subtracted from both sides)
Now substitute for 'x' in the equation y = 2x +1
y = 2(4 - y) + 1 = 8 - 2y + 1 = 9 - 2y
y = 9 - 2y can be rearranged to show 3y = 9 (Effectively adding 2y to both sides)
and by dividing by 3 then y = 3.
Now substitute the value for y in x + y = 4
x + 3 = 4 ; x = 1
Answer : x = 1, y = 3
What else can I help you with?
How do you solve 2x plus 1 equals 9?
2x + 1 = 9 2x = 9 - 1 2x = 8 2x/2 = 8/2 x=4
Solve 2x-y equals 1 2x plus 5y equals -5?
X = 0 (zero) Y = -1 (neg 1)
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x plus y equals 3. solve for x?
It can be anything. Example: x=1
How do you solve -x2 plus 2x-3?
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
How do you solve 2X plus 32 equals 1?
2x+32 = 1 2x = 1-32 2x = -31 x = -15.5
How would you solve 2x plus 1 equals 9?
2x+1 = 9 2x = 9-1 2x = 8 x = 4
How do you solve X plus 1 plus 2X equals 1X plus 5?
If: x+1+2x = 1x+5 Then: x = 2
How do you solve 2x plus 1 equals 9?
2x + 1 = 9 2x = 9 - 1 2x = 8 2x/2 = 8/2 x=4
Solve 2x-y equals 1 2x plus 5y equals -5?
X = 0 (zero) Y = -1 (neg 1)
How do you solve 2x plus 7 equals 1?
2x + 7 = 1 Therefore, 2x = -6 x = -6/2 x = -3
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x plus y equals 3. solve for x?
It can be anything. Example: x=1
How do you solve -x2 plus 2x-3?
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
Solve 2x plus 5x-1 equals 9x?
2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x
Solve 2x plus 8 equals 6?
2x+8 = 6 2x = 6-8 2x = -2 x = -1
Solve for x 2x plus two thirds equals five thirds?
2x + 2/3= 5/3 2x= 3/3 2x=1 x=1/2
