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Q: How do you solve X plus 1 plus 2X equals 1X plus 5?

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x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.

2x + 1 = 1x + 11Subtract 1x from each side:1x + 1 = 11Subtract 1 from each side:1x = 10

3x

x + 6 = 2x - 9 Add 9 to both sides: x + 15 = 2x Subtract 1x from both sides: 15 = 1x or 15 = x

2x+2=x+6 first subtract 2x. -2x -2x2=-1x+6 then subtract 6-6 -6-4=-1x finally divide by -1x=4 X equals four.

x + 3 + 2x = x + 9 x + 2x + 3 = x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 2x + 3 = 9 2x + 3 - 3 = 9 - 3 2x + 3 - 3 = 9 - 3 2x = 9 -3 2x = 6 2x/2 = 6/2 2x/2 = 6/2 x = 6/2 x = 3

First add coefficients: * 1x + 1x = 2x Second add the other values: * 4 + 5 = 9 Put it all together!: * 1x + 1x + 4 + 5 = 2x +9 * 2x + 9

2x+a=p 2x=p-a x=.5p-.5a

y= -2x

3

2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41

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