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There are equals missing from the equations, but that doesn't matter as you are asking how to solve by graphing:
First, rearrange your equations into the form: y = mx + c
You can then plot on graph paper the two equations.
In this case, they are both linear equations so the graphs will be a straight line. The easiest way to do this is to workout the y value for three chosen x values, eg x = -2, 0, 2, plot those points and draw the straight line that goes through all three. I suggest three points as it is always possible to draw a straight line through two points and as you know the line is straight, it acts as a check to ensure you have the right values.
Once you have drawn both the lines, find the point of interception (when the lines cross) - if necessary extending the lines drawn - and read off the X and Y values from the graph.
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What is yx-3 graph equation?
y=x^3
Use the Substitution method to solve the system of equationsx plus y equals -4 and x - y equals 2?
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
What is the solution of the equation yx³-3?
Without an equality sign the given expression is not an equation
How do you solve 2x plus 2y equals 4 and 4x plus y equals 1?
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
How do you solve the system by graphing -5x-y equals -2 x-3y equals 10?
Where the lines intersect that gives the values for x and y in the two equations. The lines should intersect at (1, -3) because x = 1 and y = -3
