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There are equals missing from the equations, but that doesn't matter as you are asking how to solve by graphing:

First, rearrange your equations into the form: y = mx + c

You can then plot on graph paper the two equations.

In this case, they are both linear equations so the graphs will be a straight line. The easiest way to do this is to workout the y value for three chosen x values, eg x = -2, 0, 2, plot those points and draw the straight line that goes through all three. I suggest three points as it is always possible to draw a straight line through two points and as you know the line is straight, it acts as a check to ensure you have the right values.

Once you have drawn both the lines, find the point of interception (when the lines cross) - if necessary extending the lines drawn - and read off the X and Y values from the graph.

Q: How do you solve y4x-2 and y-x 3 by graphing?

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y=x^3

x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)

2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.

Without an equality sign the given expression is not an equation

Where the lines intersect that gives the values for x and y in the two equations. The lines should intersect at (1, -3) because x = 1 and y = -3

Related questions

7-3

The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----

yx-3 is not an equation, and it has no graph.

There are several ways to solve x2-x-12. The easiest way, if you have a graphing calculator, is to put y = x2-x-12 and y = 0 into the graph and then solve for the intercepts. A way to do it without a graphing calculator is by factoring. x2-x-12 factors into (x-4) and (x+3). Then set (x-4) and (x+3) each equal to zero and solve. (x-4)=0 becomes x=4. (x+3)=0 becomes -3. Therefore, the answers are -3 and 4.

y=x^3

A graphing calculator is a calculator with the capability of graphing an equation on a built-in coordinate grid on the screen. They usually have a simple LCD grid screen, and by typing in the equation (e.g., 5x+3), the screen refreshes to display a graph of the equation in a set window range.

I don’t know

Graphing or plotting.

x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)

If you mean: y = 4x-2 and y = -x+3 then when plotted on the Cartesian plane the lines will intersect at (1, 2) because x = 1 and y = 2

2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.

Without an equality sign the given expression is not an equation