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There is no operator visible between 7 and x.
<<>> assuming that you mean y=7x in other words y equals 7 times x, that is an equation, no problem, but when you have two unknowns you have to have two equations to solve it and they have to be independent.
Example: y=7x, y=6+x are two inpdependent equations and it's possible to replace the first equation in the second, which gives 7x=6+x, in other words 6x=6 or x=1, and then either equation says that y=7.
that's impossible
7
X + y = 8 x - y = 6 add equations to eliminate y 2x = 14 x = 7 substitute 7 + y = 8 y = 1
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
y = x - 7 or, y = 1*x - 7 so that the slope is 1.
y=7+x =x=7-x
x=4 y=x+3 y=4+3 y=7
that's impossible
7
x = 12
X + y = 8 x - y = 6 add equations to eliminate y 2x = 14 x = 7 substitute 7 + y = 8 y = 1
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
y= -4x-7 y=3x 3x= -4x-7 3x+4x=7 7x=7 x=1
y = x - 7 or, y = 1*x - 7 so that the slope is 1.
To solve this system [x*7% = y], [x+y = 55], first solve for y in the second equation: y = 55-x. Then, substitute y in the first equation for 55-x: x*7%=55-x. Since x*7% is 1.07x, we can say that: 1.07x = 55-x. Then, add x to both sides to get: 2.07x = 55. Divide by 2.07, and x = 25.57. Finally substitute 25.57 for x in the second equation to get: 25.57+y = 55 , and y = 24.43. Therefore, x = 25.57, and y = 24.43
This is not Calculus.y=7(Already solved)substiute y=7 into y=8xtherefore 7 = 8xtherefore x = 7/8
y=x+4