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What expression equals 9?
[ sqrt(8)/sqrt(2) ] + [ 10/5 Hertz-seconds ] + cos(180°) + ϵ-0 - log(10) + [ sqrt(6) ]2
Factor the expression 2 k squared minus k minus 4 equals 0?
2 k^2 - k - 4 = 0 2 (k^2 - (1/2)k - 2) = 0 2 ((k - 1/4)^2 - 1/16 - 2) = 0 2 ((k - 1/4)^2 - 33/16) = 0 2 (k - 1/4 - sqrt(33)/4)(k - 1/4 + sqrt(33)/4) = 0 32 (4k - 1 - sqrt(33))(4k - 1 + sqrt(33)) = 0
Roots of the equation x 2 plus 5x plus 7 equals 0 will be?
There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2
Is a rational number times a irrational number?
Can be irrational or rational.1 [rational] * sqrt(2) [irrational] = sqrt(2) [irrational]0 [rational] * sqrt(2) [irrational] = 0 [rational]
What is the distance between points 0 4 and -4 6?
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============
What is the square root of 0 in radical form?
It is sqrt(0), which equals 0.
How many roots are in 5x2 plus 42 equals 0?
Two. x = + i sqrt(8.4) x = - i sqrt(8.4)
What expression equals 9?
[ sqrt(8)/sqrt(2) ] + [ 10/5 Hertz-seconds ] + cos(180°) + ϵ-0 - log(10) + [ sqrt(6) ]2
X squared - 2x-5 equals 0?
x2 - 2x - 5 = 0 By the quadratic equation, x = {2 +/- sqrt[(-2)2 - 4*1*(-5)]}/2 = {2 +/- sqrt(4+20)}/2 =1 +/- sqrt(6)
3P²-21P plus 35 equals 0?
3p2 - 21p + 35 = 0 Then p = [21 +/- sqrt(212 - 4*3*35)]/(2*3) = [21 +/- sqrt(441-420)]/6 = [21 +/- sqrt(21)]/6 = 2.736 and 4.264
Solve the quadratic equation x2 plus 6x plus 41 equals 0?
x = [-6 +/- sqrt(62-4*1*41)]/2 =[-6 +/- sqrt(36-164)]/2 =[-6 +/- sqrt(-128)]/2 = -3 +/- sqrt(-32) = -3 +/- i*sqrt(32) where i = the imaginary sqrt of -1
Use the quadratic formula to solve x2 - 6x plus 6 equals 0?
x=(6±sqrt(36-4*6))/2 x=3±(sqrt(12)/2) x=3±sqrt(3)
What are the values of x in this quadratic equation 2x squared-x-5 equals 0?
2x2 - x - 5 = 0 x = [1 +/- sqrt(1 + 40)]/4 = [1 +/- sqrt(41)]/4 = -1.35078 and 1.85078
How do you solve 2xsquared minus 8x plus 3 equals 0?
2x2 - 8x + 3 = 0 needs to be solved using the quadratic formula.x = (4 + sqrt(10))/2 or x = (4 - sqrt(10))/2
X2 plus 2x-4 equals 0?
x2+2x-4 = 0 x = (-2 plus/minus sqrt (4-(4x1x-4)) / 2 x = (-2 plus/minus sqrt 20)/2 x = (-2 - sqrt 20)/2 or (-2 + sqrt 20)/2 x = -3.236 or 1.236
3 times the square root of x plus 25 times x equals 0?
Is this 3*sqrt((x+25)*x)=0 or 3*sqrt(x+25x)=0 or 3*sqrt(x)+25x=0 or 3*sqrt(x+25)*x=0? I'm not going to bother answering all possible interpretations, but here's a hint: square the equation to get rid of the square root operation first. Then solving it will be easy.
What is the nature of the solutions of the equation x2 plus 11 equals 0?
The two solutions are the conjugate complex numbers, +i*sqrt(11) and -i*sqrt(11), where i is the imaginary square root of -1.
