Substitute 5 for x and solve: 8 + 6(5) = ?
6x - 3b + 8 = 16.Since you cannot simplify the equation, the answer is 6x - 3b = 8.However, if you would like to find x, you can substitute b with '0':6x - 3b + 8 = 166x - 3b = 86x - 3(0) = 86x = 86 6x = 1.33 or 1(1/3)If you want to find b, you can substitute x with '0':6x - 3b + 8 = 166x - 3b = 86(0) - 3b = 8-3b = 8-3 -3b = -2.66 or -2(2/3)
To solve the equation for either y or x, you need to have a value for the variable you are not trying to solve for. For example, if you're solving for x in y = -6x + 1, when y = 0: 0 = -6x + 1 (substitute 0 for y) 6x = 1 (add 6x to both sides) x = 1/6 (divide both sides by 6)
If you mean: -10+4y = 12 then it is y = 2.5x+3
From first equation y = 3x + 5. Substitute this in second equation 2(3x + 5) = 6x + 10 This proves that 6x + 10 = 6x + 10 which is not helpful! I suppose possible solutions would be x = 0, y = 5 or x = 1, y = 8 etc etc Are you sure of your two equations, please?
the solution to the system of equations 6x + 7y = 20 and y = 2x is (x, y) = (1, 2)
Substitute 5 for x and solve: 8 + 6(5) = ?
6x - 3b + 8 = 16.Since you cannot simplify the equation, the answer is 6x - 3b = 8.However, if you would like to find x, you can substitute b with '0':6x - 3b + 8 = 166x - 3b = 86x - 3(0) = 86x = 86 6x = 1.33 or 1(1/3)If you want to find b, you can substitute x with '0':6x - 3b + 8 = 166x - 3b = 86(0) - 3b = 8-3b = 8-3 -3b = -2.66 or -2(2/3)
x=4 y=1 Therefore, 6x+5y=? Just substitute, and get 6*4+5*1=29
Only when you multiply or divide by a negative number
To solve the equation for either y or x, you need to have a value for the variable you are not trying to solve for. For example, if you're solving for x in y = -6x + 1, when y = 0: 0 = -6x + 1 (substitute 0 for y) 6x = 1 (add 6x to both sides) x = 1/6 (divide both sides by 6)
First of all, you have two equations.Y=6X-11 -2X-3Y=-7What you should do is substitute the Y in equation two with 6X-11. Now Y is gone from equation two. Solve for X. Substitute the value of X into equation one to find the Y value.First, substitute Y in equation two with equation one (excluding the isolated Y):-2X-3Y=-7-2X-3(6X-11)=-7-2X-18X+33=-7-20X+33-33=-7-33-20X=-40-20/-20X=-40/-20X=2Now we would substitute X in equation one with the X value of 2:Y=6X-11Y=6(2)-11Y=12-11Y=1Therefore, X=2 and Y =1.
If you mean: y = 6x-4 and y = 7x-7 then by substitution x = 3 and y = 14
If you mean: -10+4y = 12 then it is y = 2.5x+3
From first equation y = 3x + 5. Substitute this in second equation 2(3x + 5) = 6x + 10 This proves that 6x + 10 = 6x + 10 which is not helpful! I suppose possible solutions would be x = 0, y = 5 or x = 1, y = 8 etc etc Are you sure of your two equations, please?
3x-6y=30 y=34-6x substitute the the value for y from the second equation into the first equation. 3x-6(34-6x)=30 3x-204+36x=30 39x-204=30 39x=234 x=234/39 x=6 Substitute this value of x into equation 2. y=34-6(6) y=34-36 y=-2
First, you would have to eliminate a variable. Let's multiply each side of the second equation by two. 7y - 3x = -11 => 14y - 6x = -22 => -6x + 14y = -22 Now you have two new equations: 6x - 9y = 19.5 -6x + 14y = -22 Now add the two equations together to eliminate the variable. 0x + 5y = -2.5 => 5y = -2.5 => y = -0.5 Substitute y = -0.5 into an original equation. 6x - 9y = 19.5 => 6x - 9(-0.5) = 19.5 => 6x - (-4.5) = 19.5 => 6x = 15 => x = 2.5 The answer is: x = 2.5 y = -0.5 or as an ordered pair: (2.5,-0.5)