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What is a solution to the following system of equations using substitution -5x plus y equals -5?
-10
How can you use substitution method to solve a system of equations that does not have a variable with a coefficient of 1 or - 1?
To use the substitution method on a system of equations without a variable with a coefficient of 1 or -1, you first isolate one variable in one of the equations. For instance, if you have the equations (2x + 3y = 6) and (4x - y = 5), you can solve the first equation for (y), resulting in (y = (6 - 2x)/3). Next, substitute this expression for (y) into the second equation, allowing you to solve for (x). Finally, substitute the value of (x) back into one of the original equations to find the corresponding value of (y).
Which points are on the line given by the equation y5x?
If you mean: y = 5x then it has a slope of 5 and passes through the origin of (0, 0)
What is the y-intercept of the line given by the equation y5x 16?
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
Solve the simultanius equations 3x - y equals 11 and x plus y equals 5?
3x-y = 11 x+y = 5 Add both equations together: 4x = 16 Divide both sides by 4 to find the value of x: x = 4 Substitute the value of x into the original equations to find the value of y: Therefore: x = 4 and y = 1
What is the slope and y-intercept of y5x-7?
12
Solve the system using substitution 5x-y equals 5 diveded by5x-3y equals 15?
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
What is the gradient of the line y5x-1?
6
What is a solution to the following system of equations using substitution -5x plus y equals -5?
-10
How can you use substitution method to solve a system of equations that does not have a variable with a coefficient of 1 or - 1?
To use the substitution method on a system of equations without a variable with a coefficient of 1 or -1, you first isolate one variable in one of the equations. For instance, if you have the equations (2x + 3y = 6) and (4x - y = 5), you can solve the first equation for (y), resulting in (y = (6 - 2x)/3). Next, substitute this expression for (y) into the second equation, allowing you to solve for (x). Finally, substitute the value of (x) back into one of the original equations to find the corresponding value of (y).
Y equals x plus 3 and 3x-y equals 5?
Solve this simultaneous equation using the elimination method after rearraging these equations in the form of: 3x-y = 5 -x+y = 3 Add both equations together: 2x = 8 => x = 4 Substitute the value of x into the original equations to find the value of y: So: x = 4 and y = 7
Which points are on the line given by the equation y5x?
If you mean: y = 5x then it has a slope of 5 and passes through the origin of (0, 0)
How do you solve y5x 6.50?
If you mean: y = 5x+6.50 then it is a straight line equation whose slope is 5 with a y intercept of 6.5
What is the y-intercept of the line given by the equation y5x 16?
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
Solve the simultanius equations 3x - y equals 11 and x plus y equals 5?
3x-y = 11 x+y = 5 Add both equations together: 4x = 16 Divide both sides by 4 to find the value of x: x = 4 Substitute the value of x into the original equations to find the value of y: Therefore: x = 4 and y = 1
How do you solve 2x plus y equals 8 y equals -x plus 5 substitution method?
2x+y = 8 y = -x+5 Substitute y for -x+5 into the first equation: 2x+(-x+5) = 8 2x-x+5 = 8 x = 8-5 x = 3 Substitute the value of x into the original equations to find the value of y: x = 3 and y = 2
7x - 5y equals 76 4x plus y equals 55?
To solve this system of equations, we can use the method of substitution or elimination. Let's use the substitution method. From the second equation, we can express y as y = 55 - 4x. Substitute this expression for y in the first equation: 7x - 5(55 - 4x) = 76. Simplify this equation to solve for x. Then, substitute the value of x back into one of the original equations to find the value of y.
