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To use the substitution method on a system of equations without a variable with a coefficient of 1 or -1, you first isolate one variable in one of the equations. For instance, if you have the equations (2x + 3y = 6) and (4x - y = 5), you can solve the first equation for (y), resulting in (y = (6 - 2x)/3). Next, substitute this expression for (y) into the second equation, allowing you to solve for (x). Finally, substitute the value of (x) back into one of the original equations to find the corresponding value of (y).
If you mean: y = 5x then it has a slope of 5 and passes through the origin of (0, 0)
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
3x-y = 11 x+y = 5 Add both equations together: 4x = 16 Divide both sides by 4 to find the value of x: x = 4 Substitute the value of x into the original equations to find the value of y: Therefore: x = 4 and y = 1
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5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
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To use the substitution method on a system of equations without a variable with a coefficient of 1 or -1, you first isolate one variable in one of the equations. For instance, if you have the equations (2x + 3y = 6) and (4x - y = 5), you can solve the first equation for (y), resulting in (y = (6 - 2x)/3). Next, substitute this expression for (y) into the second equation, allowing you to solve for (x). Finally, substitute the value of (x) back into one of the original equations to find the corresponding value of (y).
Solve this simultaneous equation using the elimination method after rearraging these equations in the form of: 3x-y = 5 -x+y = 3 Add both equations together: 2x = 8 => x = 4 Substitute the value of x into the original equations to find the value of y: So: x = 4 and y = 7
If you mean: y = 5x then it has a slope of 5 and passes through the origin of (0, 0)
If you mean: y = 5x+6.50 then it is a straight line equation whose slope is 5 with a y intercept of 6.5
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
3x-y = 11 x+y = 5 Add both equations together: 4x = 16 Divide both sides by 4 to find the value of x: x = 4 Substitute the value of x into the original equations to find the value of y: Therefore: x = 4 and y = 1
2x+y = 8 y = -x+5 Substitute y for -x+5 into the first equation: 2x+(-x+5) = 8 2x-x+5 = 8 x = 8-5 x = 3 Substitute the value of x into the original equations to find the value of y: x = 3 and y = 2
To solve this system of equations, we can use the method of substitution or elimination. Let's use the substitution method. From the second equation, we can express y as y = 55 - 4x. Substitute this expression for y in the first equation: 7x - 5(55 - 4x) = 76. Simplify this equation to solve for x. Then, substitute the value of x back into one of the original equations to find the value of y.