Suppose x and y are two rational number.Then x = p/q and y = r/s where p, q, r and s are integers, with q and s being non-zero.
Then x - y = p/q - r/s = pq/qs - qr/qs = (pq - rs)/qs.
The signs of x and y do not matter, in so far as their signs will be used to determine the signs of p,q, r and s.
Then you are adding two rational numbers with different signs! No big deal!
You add all the numbers with + signs and subtract all that have minus signs.
In addition different signs you subtract and give the sign of the bigger number. Ex: 6+(-8)= -14
Adding two numbers with different signs means subtracting the two absolute integers (without sign) and vice versa.
The numerical value is the same as the quotient of the two positive equivalents but the sign is always negative.
Then you are adding two rational numbers with different signs! No big deal!
You add all the numbers with + signs and subtract all that have minus signs.
It the two rational numbers have different signs, then the answer will be negative, otherwise it will be positive.
The quotient is negative.
sometimes true (when the rational numbers are the same)
No; depends on the signs of the rational numbers.
In addition different signs you subtract and give the sign of the bigger number. Ex: 6+(-8)= -14
The sign of the sum is positive when the absolute value of the positive addend is greater than that of the negative addend.
Adding two numbers with different signs means subtracting the two absolute integers (without sign) and vice versa.
The numerical value is the same as the quotient of the two positive equivalents but the sign is always negative.
By the signs: 2+2(Add) 2-2(Subtract) +=add -=subtract
The answer depends on the numbers under the radical signs. Dpending on their value, the answer will be rational, irrational (real) or complex.