no
It's something just over 9 (93 = 729). One way to find it is with a calculator: take the logarithm of 769, divide it by 3 then take the anti-log.
You have, y = 6 + log x anti log of it, 10y = (106) x
You can do it directly on a calculator and get 1.2676506002282e+30. Or you can use logs like y=n^5 and log y=5*log(1048576)=30.102999566398. Look up the anti-log for the answer.
let x and y be two numbers ex = y log y = x antilog x = y
no
log(10) 12 = 1.07918 Then the antilog is 12 = 10^(1.07918) You must specify the base to which to logarithm is functioning. Different log bases will give different answers.
To find anti log of a number enter the number as the exponent of 10.
The anti-log of 12.34 is the inverse operation of taking the logarithm of a number. In this case, the anti-log of 12.34 is equal to 10^12.34, which is approximately 2511886431. A logarithm is the power to which a base must be raised to produce a given number, so the anti-log reverses this operation to find the original number.
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log(24.6992) = 1.392682887 Now the anti-log. 101.392682887 = 24.6992 ---------------
anti-log 36 is base36 Without any qualification "log n" is the "logarithm to any base of n"; though it is often used for common logs, or logs to base 10 (log10 n), which is often abbreviated to lg. On a calculator, the [log] button is used for common logs to base 10, so anti-log 36 = 1036
Without antilog tables or a scientific calculator you cannot. Antilog(x) is usually 10x or ex and that is not simple to calculate.
It's something just over 9 (93 = 729). One way to find it is with a calculator: take the logarithm of 769, divide it by 3 then take the anti-log.
You have, y = 6 + log x anti log of it, 10y = (106) x
You can do it directly on a calculator and get 1.2676506002282e+30. Or you can use logs like y=n^5 and log y=5*log(1048576)=30.102999566398. Look up the anti-log for the answer.
let x and y be two numbers ex = y log y = x antilog x = y