Three basic log rules when dealing with logarithms are multiplication inside the log can be turned into addition outside the log, division inside the log can be turned into subtraction outside the log, an exponent on everything inside a log can be moved out front as a multiplier vice versa.
In order to find the log with a power of ten, use the LOG button. For example, to find log105, type log(5). (The parenthesis after the g will appear when you press the LOG button. In order to find a log with a power other than ten, you will have to divide by the log10 of that power. For example, to find log82, type log(8)/log(2). In order to find the natural log of a number, use the LN key. For example, to find the natural log of 91, type ln(91).
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
You have, y = 6 + log x anti log of it, 10y = (106) x
19, of course. Review your logarithmic rules.
Three basic log rules when dealing with logarithms are multiplication inside the log can be turned into addition outside the log, division inside the log can be turned into subtraction outside the log, an exponent on everything inside a log can be moved out front as a multiplier vice versa.
To find anti log of a number enter the number as the exponent of 10.
log(24.6992) = 1.392682887 Now the anti-log. 101.392682887 = 24.6992 ---------------
The anti-log of 12.34 is the inverse operation of taking the logarithm of a number. In this case, the anti-log of 12.34 is equal to 10^12.34, which is approximately 2511886431. A logarithm is the power to which a base must be raised to produce a given number, so the anti-log reverses this operation to find the original number.
I'm not sure if there are four set rules, but generally:Don't get caught by muggles (non geocachers).Log your find in the logbook and on the website.If you take something, leave something of equal or greater value.Place the cache back where you found it.
log(10) 12 = 1.07918 Then the antilog is 12 = 10^(1.07918) You must specify the base to which to logarithm is functioning. Different log bases will give different answers.
home mean
Some basic logarithm rules appear in related links.
You Log Off
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
It is simply 10 to that power. Thus, antilog(231) = 10231. Could not be simpler.
anti-log 36 is base36 Without any qualification "log n" is the "logarithm to any base of n"; though it is often used for common logs, or logs to base 10 (log10 n), which is often abbreviated to lg. On a calculator, the [log] button is used for common logs to base 10, so anti-log 36 = 1036