0
If ...
the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle)
added to
the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle)
is equal to
the square of the circle's radius,
then the point is on the circle.
What else can I help you with?
Which point lies outside the circle with equation (x - 2)2 (y 3)2 4?
2,0
What point lies on the circle whose center is at the origin and whose radius is 10?
There are infinitely many points. One of these is (10, 0).
Which point lies on a circle with a radius of 5 units and center at P6 1?
There are infinitely many such points. One of them is: (2,236, 4.291)
In the straightedge and compass construction of an equilateral triangle below reasons can you use to prove that ab and ac are congruent?
To prove that segments ( ab ) and ( ac ) are congruent in the construction of an equilateral triangle, you can use the property of circles. When you draw a circle with center ( a ) and radius ( ab ), point ( b ) lies on this circle. Similarly, if you draw a circle with center ( a ) and radius ( ac ), point ( c ) lies on this circle as well. Since both circles are constructed with the same radius from point ( a ), it follows that ( ab = ac ), proving that segments ( ab ) and ( ac ) are congruent.
What is the center point of a circle?
The point from which the circle is drawn IS the center.
Is each point that lies on a circle satisfies the equation of the circle true or false?
True
Which point lies outside the circle with equation (x - 2)2 (y 3)2 4?
2,0
The center of a circle lies on what?
Every diameter of the circle.
Greenland lies primarily in what circle?
the artic circle
What are the ratings and certificates for Circle of Lies - 2012?
Circle of Lies - 2012 is rated/received certificates of: Australia:MA15+ (2013)
Which point lies on a circle with a radius of 5 units and center at P6 1?
There are infinitely many such points. One of them is: (2,236, 4.291)
What point lies on the circle whose center is at the origin and whose radius is 10?
There are infinitely many points. One of these is (10, 0).
C program to find whether the given point lies inside or outside or in circle?
I'm not going to write the program for you, but the way to determine whether a point lies within a circle is very easy: just compare the distance between the point and the centerpoint of the circle with its radius. If the distance is smaller, it's inside the circle, if it's greater, then the point is outside.You can calculate the distance between the point and the centerpoint using Pythagoras's method. If the point is at (PX, PY) and the centerpoint is at (CX, CY), the distance can be calculated as such:DX = (CX - PX); // X distanceDY = (CY - PY); // Y distancedistance = sqrt( (DX * DX) + (DY * DY) );
In the straightedge and compass construction of an equilateral triangle below reasons can you use to prove that ab and ac are congruent?
To prove that segments ( ab ) and ( ac ) are congruent in the construction of an equilateral triangle, you can use the property of circles. When you draw a circle with center ( a ) and radius ( ab ), point ( b ) lies on this circle. Similarly, if you draw a circle with center ( a ) and radius ( ac ), point ( c ) lies on this circle as well. Since both circles are constructed with the same radius from point ( a ), it follows that ( ab = ac ), proving that segments ( ab ) and ( ac ) are congruent.
Which point lies on a circle that is centered at A-3 2 and passes through B1 3?
There are infinitely many points. One of these is (-7, 1)
How to draw great circles and small circles drawn?
To draw a great circle on a sphere, start by defining the diameter as the largest circle that can be drawn on the sphere's surface. For small circles, choose a point on the sphere and draw a circle with that point as the center and the radius less than the sphere's radius. Remember that the center of a small circle lies outside the circle on a sphere's surface.
What are the release dates for Circle of Lies - 2012?
Circle of Lies - 2012 was released on: USA: 1 December 2012 (The Amaz!ng Meeting)
