2,0
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
True. The solution set of an equation of a circle consists of all the points that lie on the circle. This is defined by the standard equation of a circle, which is typically in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Any point ((x, y)) that satisfies this equation lies on the circle.
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, representing the circle's boundary. Typically, this equation is in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Each point ((x, y)) that meets this condition lies exactly on the circle.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
True
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
True. The solution set of an equation of a circle consists of all the points that lie on the circle. This is defined by the standard equation of a circle, which is typically in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Any point ((x, y)) that satisfies this equation lies on the circle.
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, representing the circle's boundary. Typically, this equation is in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Each point ((x, y)) that meets this condition lies exactly on the circle.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
A. The hexagon is circumscribed about the circle . D. Each vertex of the hexagon lies outside the circle . E. The circle is tangent to each side of the hexagon .
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, which typically takes the form ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is its radius. Any point ((x, y)) that lies on the circle will fulfill this equation, thus forming the complete solution set.
It seems there is a small error in the equation you provided; it should likely be in the form of (3x - 2y = 10). To determine if a point lies on this line, you can substitute the x and y coordinates of the point into the equation. If the equation holds true, then the point lies on the line. For example, if the point is (4, 1), substituting gives (3(4) - 2(1) = 12 - 2 = 10), which is true, so the point (4, 1) lies on the line.
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
Without an equality sign it can not be considered to be an equation
To draw a great circle on a sphere, start by defining the diameter as the largest circle that can be drawn on the sphere's surface. For small circles, choose a point on the sphere and draw a circle with that point as the center and the radius less than the sphere's radius. Remember that the center of a small circle lies outside the circle on a sphere's surface.