Imagine the wire is straight, now cut through at right angle to the centre line, the exposed surface is the cross sectional area, on a round wire it = pi * radius2 (area of a circle)
Simply work out the area of a section of cable.........
It is possible, depending on what you do know. If you have the radius, you can work out the cross sectional area. Measure the volume - by the displacement method. Then volume/cross section = height.
That would depend on the cross sectional area of that linear meter of steel and as you have not told us that we can not answer you. To work out the answer for yourself you need to know the VOLUME of your steel and you multiply this by the density of your steel to give you a weight.
You have to work out the area of the cross section (the circle at the top) So if lateral surface area (LSA) is 2*pi*r*height rearrange to work out the radius (height = LSA/2/pi/r) then use pi * r2 to work out the area of the cross section then times the area of the cross section by the height Overall, this yields the formula: Volume = pi*r2*LSA/2/pi/r = r*LSA/2
Imagine the wire is straight, now cut through at right angle to the centre line, the exposed surface is the cross sectional area, on a round wire it = pi * radius2 (area of a circle)
cross-sectional area = 0.5*(sum of parallel sides)*height
Simply work out the area of a section of cable.........
It is possible, depending on what you do know. If you have the radius, you can work out the cross sectional area. Measure the volume - by the displacement method. Then volume/cross section = height.
Work it out for yourself. The equation you will need to use is: resistance = resistivity x (cross-sectional area / length) Manipulate the equation to make 'length' the subject, and use 17.25 x 10-9 ohm metres as the value of resistivity.
as every size bar differ in diameter and possibly type, the reinforcement steel is measured in kilograms per meter, say 8.5kg/m. the steel weight is actually calculated, as a % of the cross-sectional area. different applications have different minimum % steel required, roughly work on 1%. the sum of the bars cross sectional area at each support and spans are seperately calculated and compared to the cross sectional area of the concrete, hence expressed as a %.
To work out the mass of wire you need to know its volume. The wire is circular so that volume would just be the cross sectional area (pi * r^2) multiplied by the length of wire. Lets call the length L. The equation is then volume = pi * radius^2 * L. To get the mass of the wire we now multiply this equation by denstiy of the wire; that is how much the wire weighs per volume. Assuming the wire is steel this would be around 800Kg/m^3. So what you want to do is work out the volume as above, then multiply by 800, making sure that your units are consistant....ie lenght and radius in metres.
That would depend on the cross sectional area of that linear meter of steel and as you have not told us that we can not answer you. To work out the answer for yourself you need to know the VOLUME of your steel and you multiply this by the density of your steel to give you a weight.
The main function of a dial vernier caliper is to accurately measure the dimensions of an object with high precision. It has a dial indicator to provide a digital reading of the measurements, making it easier to read and record data. This type of caliper is commonly used in engineering, manufacturing, and research applications.
Treat it as 3 rectangles.
No, a single 8 AWG wire cannot be replaced by two 10 AWG wires in terms of electrical capacity and current-carrying capability. The 8 AWG wire has a larger cross-sectional area and can handle more current compared to two 10 AWG wires combined. It's important to match the wire gauge with the specific requirements of the circuit to ensure safety and proper functioning.
Imagine that you wanted to cut a globe or a sphere exactly in half. When you looked at the cut you would see an exact circle on both pieces. This area would be the cross-section. You could work out the area of this cross-section by using A = Pi X r squared. But be careful. Don't assume that the cross sectional area is the same no matter where you cut. If you cut the globe at some other point, say near to the edge, the cross-section (the circular area that you would see) would be a lot smaller. You would come across a uniform cross-section if you cut a cable. No matter where you cut the cable the cross-section should be roughly the same. Also cross section doesn't have to be circular. The cross-section you get really depends on the original shape you are dealing with. If you cut a cube in half, you would get a square cross-section. So I guess you could imagine the term as applying to cutting across (hence cross) something to reveal 2 sections (hence section).