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It depends on what angle. The main angles of a rectangle are all 90 degrees and knowing that does not help. If however, the angle in question is the angle made by the diagonal with one of the sides, then it is possible to use a basic trigonometric ratio to work out the length. Details will depend on which angle is given.

Q: How do you work out the length of a rectangle with the width and an angle?

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The width of a rectangle is the length of the shorter side.

measure it

That is the definition of the area of a rectangle. It does not work for any other shape.

area is................ length x width perimeter is .......... length x width x length x width * * * * * WRONG. Area is the amount of space occupied by a shape. In the case of a rectangle, it is length x width, as stated above. But that does not work for circles, ellipses, triangles, other quadrilaterals and polygons and many other shapes, all of which have areas. A perimeter is the sum of all the lengths bordering the shape. The perimeter of a rectangle is NOT length x width x length x width but their sum! But again, that does not work for most other shapes.

W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42

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The width of a rectangle is the length of the shorter side.

measure it

To work out the area of a rectangle, multiply the length and the width. Therefore: Area=23*20=460

Its width is 11.5 cm.Knowing that, it will be easy for you to reproduce the work.

That is the definition of the area of a rectangle. It does not work for any other shape.

What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in

area is................ length x width perimeter is .......... length x width x length x width * * * * * WRONG. Area is the amount of space occupied by a shape. In the case of a rectangle, it is length x width, as stated above. But that does not work for circles, ellipses, triangles, other quadrilaterals and polygons and many other shapes, all of which have areas. A perimeter is the sum of all the lengths bordering the shape. The perimeter of a rectangle is NOT length x width x length x width but their sum! But again, that does not work for most other shapes.

The dimensions work out as length = 9 and width = 5

Length multiplied by width equals the area of a square or rectangle A=LxW Your answer will be in units squared.

To work out the area of a square or a rectangle, all you need to do is multiply the length by the width. In this case the room is the rectangle, and its length is 6 metres and its width is 4 metres. So its area is 6m x 4m = 24sqm.

W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42

If you pretend that the width is X .Then you'll know that X times length = area. So if you say the length is 5 ,then the area is 10 the X must be 2 so the width is 2you simply work out what times the length makes the area.