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That is the definition of the area of a rectangle. It does not work for any other shape.
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∙ 13y ago
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How To work out Area?
You times length by width
What is the difference between an area and perimeter?
area is................ length x width perimeter is .......... length x width x length x width * * * * * WRONG. Area is the amount of space occupied by a shape. In the case of a rectangle, it is length x width, as stated above. But that does not work for circles, ellipses, triangles, other quadrilaterals and polygons and many other shapes, all of which have areas. A perimeter is the sum of all the lengths bordering the shape. The perimeter of a rectangle is NOT length x width x length x width but their sum! But again, that does not work for most other shapes.
How may square foot for 6feetx6feet?
to work out the area, times the length by the width.6x6=36
How do you work out find out the area when the length is twice the with?
You just multipy the length (no matter what it is) by the width (no matter what that is). So... L x W = A Where L is Length, W is Width and A is Area. For your question about the area of a rectangle where the length is twice the width but no numbers are given then I guess a formula could be W x 2W = A. Or send me the exact question and I'll see if I can think of a better answer.
Why the formula Length times Width times height work for finding the volume?
X * X * X = X3 All three dimensions are covered by finding volume and this is a cubic function.
How To work out Area?
You times length by width
How do you work out the length and width of a square?
The length and width of a square are equal. Thus, find the square root of the area and the answer = length= width.
How do you work out find out the area when the length is twice the width?
length*width = 2*width*width i.e square the width and multiply by 2
What is the area of a rectangle that has a length of 23 a width of 20 and a height of 67?
To work out the area of a rectangle, multiply the length and the width. Therefore: Area=23*20=460
How do you work out the area of an object mathematically?
Length x width
How do you find the width of a rectangle if you know its length and its area?
If you pretend that the width is X .Then you'll know that X times length = area. So if you say the length is 5 ,then the area is 10 the X must be 2 so the width is 2you simply work out what times the length makes the area.
The fast complex volleyball court has an area of 132 m² if the width of the court is 6 m what is the length of the court?
this answer is simply division just for a reminder of what I am doing here are how to work these length times width = area area divided by width = length area divided by length = width. we will be doing the second equation so 132 divided by 6 = 22 answer is 22
How do you work out the squared meter area of a room?
width times length multiplied.
How do you work out what the square meter of an area is?
If it is a quadrilateral, you take the length times the width.
What is the difference between an area and perimeter?
area is................ length x width perimeter is .......... length x width x length x width * * * * * WRONG. Area is the amount of space occupied by a shape. In the case of a rectangle, it is length x width, as stated above. But that does not work for circles, ellipses, triangles, other quadrilaterals and polygons and many other shapes, all of which have areas. A perimeter is the sum of all the lengths bordering the shape. The perimeter of a rectangle is NOT length x width x length x width but their sum! But again, that does not work for most other shapes.
What is the width of a rectangle with length 14 cm and area 161 cm2 show all the work?
Its width is 11.5 cm.Knowing that, it will be easy for you to reproduce the work.
What Sides of a rectangle give perimeter equal to to area?
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.
