By dividing it into two rectangles.
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Divide it into 2 pieces and work out the volume of each piece separately and then add the volumes together
The volume of a cuboid with sides of length L, B and H is L*B*H cubic units.
If it is a small shape that is denser than a convenient fluid and insoluble in it and also does not react with it then the displacement method is simplest. Fill a graduated cylinder with the fluid, measure the volume of the fluid. Then gently insert the shape and measure the apparent volume of the fluid. The difference between the two volume readings is the volume of the shape. If the shape is less dense than the fluid you have to make one change. You need to find a dense insoluble object. Measure the volume of the fluid with the dense object immersed in it. Then measure the volume when the dense object and the shape are joined together and submerged. The difference between the two measures is the volume of the shape. This method will not work with soluble shapes unless you can find a fluid that it is not soluble in. Similarly, you cannot use a fluid that will react. So measuring the volume of a lump of sugar or a lump of sodium using water are non-starters. Finally, the method will not work if the irregular shape is huge.
The answer depends on whether or not the tank has a geometric shape. If it has a shape that can be broken up into simply geometric shapes, each with a volume formula, you can calculate the volume of each section and add them together. Obviously that will not work with a random shape. In that case, you can fill the tank to capacity and then empty it out into measuring jars or flasks. Use the volume of the jars to calculate the volume of the tank.
Solids have a fixed volume or shape at room temperature or pressure.