First find the area of the square (length x width) then find the area of the triangle (base x height x 2) and add the two answers together.
Quadrilateral just means "four sides", but the sides have to be straight.
Assuming it's a right-angle triangle? Such a triangle is half of a rectangle or square, so times by 2).
If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
The only thing that can be said is that the quadrilateral will have an area that is smaller than the square. The exact value depends on the location of the vertices.
If you mean: 2x+3y = 6 then the coordinates are (3, 0) and (0, 2) giving the triangle an area of 3 square units
Because - if you draw lines at right-angles from the base of a triangle vertically until they reach the highest point, then draw a horizontal line that connects those points, touching the highest point of the triangle - the area outside the triangle (but inside the resulting quadrilateral) is exactly half the area of the quadrilateral.
By plotting the given vertices and then joining them together on the Cartesian plane the shape of a isosceles triangle will be formed with an area of 78 square units.
It's half the size of a quadrilateral with 24 square units ------------ One type of triangle with an area of 12 square units is the isosceles triangle with two 5-unit sides and one 6-unit side.
If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
Because in effect a triangle is half of a 4 sided quadrilateral
You do not indicate if the given area is the total area of the square and the triangle. Or whether they are equal values.
The only thing that can be said is that the quadrilateral will have an area that is smaller than the square. The exact value depends on the location of the vertices.
Because a triangle is the half shape of a 4 sided quadrilateral
If you mean: 2x+3y = 6 then the coordinates are (3, 0) and (0, 2) giving the triangle an area of 3 square units
Because - if you draw lines at right-angles from the base of a triangle vertically until they reach the highest point, then draw a horizontal line that connects those points, touching the highest point of the triangle - the area outside the triangle (but inside the resulting quadrilateral) is exactly half the area of the quadrilateral.
By using Pythagoras' theorem the quadrilateral will have a diagonal of 5 cm thus dividing the quadrilateral into two triangles and then by finding the area of each triangle the area of the quadrilateral works out as 16.69 square cm rounded to two decimal places.
By plotting the given vertices and then joining them together on the Cartesian plane the shape of a isosceles triangle will be formed with an area of 78 square units.
It is normally length times perpendicular height for most of them.
That would depend on the dimension of the green triage. If the triangle was formed by joining two opposite corners of the parallelogram then it would be half the area of the parallelogram. Area of parallelogram = 15*2 = 30 square cm. 1/2 the area = 15 square cm.