-- The decimal system (base-10) uses 10 digits to write all numbers. -- The binary system (base-2) uses 2 digits to write all numbers.
This is my own way of finding a binary of a number. We all know that binary is in base 2 (it only have 2 values - 0 and 1). Here is how I do it:Steps:1) Divide the number by 2. If there is a remainder, then write the number 1 as the first binary number otherwise write 0.Ex:7/2 = 3.5 ---> Since there's a remainder write 1.8/2 = 4 ---> If there's no remainder write 0.2) Repeat the first step using the value that was derived on the first one. Continue doing so until the number is not less than 1Ex:3/2 = 1.5 ---> Our binary now is 11.4/2 = 2 ---> Our binary here is 00.Repeat:1/2 = 0.5 ---> Since the number is less than zero, just write the final result. Our binary now is 111.2/2 = 1 ---> Again here we write 000.1/2 = 0.5 ---> Now we write it as 0001.3) After getting the final value, reverse your answer and it will now be the binary form.Answer:710 = 1112810 = 10002Note: Please edit my answer if you are a bit confuse with the steps.
Two, 11 in binary, II in roman numerals
Decimal 18 is 10010 in binary
Decimal 26 is 11010 in binary
When you write the decimal number '7' in Base-2 (binary), you write '0111'.
2 --------- 10
Binary 1001111 is 79 in decimal.
'2' Decimal code => '10' Binary code.
First let's write it as a sum of powers of two. This will make it easier to write as a binary number. 19=16+2+1 This can be written: 19=16*1+8*0+4*0+2*1+1*1 So the binary form is: 10011
-- The decimal system (base-10) uses 10 digits to write all numbers. -- The binary system (base-2) uses 2 digits to write all numbers.
This is my own way of finding a binary of a number. We all know that binary is in base 2 (it only have 2 values - 0 and 1). Here is how I do it:Steps:1) Divide the number by 2. If there is a remainder, then write the number 1 as the first binary number otherwise write 0.Ex:7/2 = 3.5 ---> Since there's a remainder write 1.8/2 = 4 ---> If there's no remainder write 0.2) Repeat the first step using the value that was derived on the first one. Continue doing so until the number is not less than 1Ex:3/2 = 1.5 ---> Our binary now is 11.4/2 = 2 ---> Our binary here is 00.Repeat:1/2 = 0.5 ---> Since the number is less than zero, just write the final result. Our binary now is 111.2/2 = 1 ---> Again here we write 000.1/2 = 0.5 ---> Now we write it as 0001.3) After getting the final value, reverse your answer and it will now be the binary form.Answer:710 = 1112810 = 10002Note: Please edit my answer if you are a bit confuse with the steps.
All possible 2-bit numbers ... 0, 1, 2, and 3 ... are the same in BCD and binary. No conversion is required.
Two, 11 in binary, II in roman numerals
You write the number as a sum of decreasing powers of 2. Then for each power, you write 1 if it is present in the sum and 0 if not.So, 3 = 2 + 1 = 2^1 + 2^0and so the binary for 3 (in decimal) is 11.
Decimal 23 is 10111 in binary
Decimal 18 is 10010 in binary