In today's notation of Roman numerals it written out as: DXCIX But the Romans themselves probably wrote it out simply as IDC (600-1 = 599)
x + y = 3, y = -x + 3 xy = 152 x(-x + 3) = 152 -x2 + 3x = 152 x2 - 3x = -152 form the square x2 - 3x + (3/2)2 = (3/2)2 - 152 (x - 3/2)2 = 9/4 - 152 x - 3/2 = ±√[(9 - 152*4)/4] x = 3/2 ± (√-599)/2 x = (3 ± i√599)/2 x = (3 + i√599)/2 or x = (3 - i√599)/2 y = 3 - x y = 3 - (3 + i√599)/2 y = (6 - 3 - i√599)/2 y = (3 - i√599)/2 or y = (3 + i√599)/2 Check: [(3 + i√599)/2][(3 - i√599)/2] = [32 - (i√599)2]/4 = (9 - 599i2)/4 =( 9 + 599)/4 = 608/4 = 152 (3 + i√599)/2 + (3 - i√599)/2 = (3 + i√599 + 3 - i√599)/2 = 6/2 = 3
yes 599 is prime
Yes - 599 is an integer.
599
0.307
he wrote 599 poems
In today's notation of Roman numerals it written out as: DXCIX But the Romans themselves probably wrote it out simply as IDC (600-1 = 599)
67.1% of 599= 67.1% * 599= 0.671 * 599= 401.929
599% = 599/100 in fraction
1 and 599 (599 is a prime number).
The answer is 1418 followed by 599 zeroes. You can also write the answer as 1.1481306952742545242328332011777 x 10602
x + y = 3, y = -x + 3 xy = 152 x(-x + 3) = 152 -x2 + 3x = 152 x2 - 3x = -152 form the square x2 - 3x + (3/2)2 = (3/2)2 - 152 (x - 3/2)2 = 9/4 - 152 x - 3/2 = ±√[(9 - 152*4)/4] x = 3/2 ± (√-599)/2 x = (3 ± i√599)/2 x = (3 + i√599)/2 or x = (3 - i√599)/2 y = 3 - x y = 3 - (3 + i√599)/2 y = (6 - 3 - i√599)/2 y = (3 - i√599)/2 or y = (3 + i√599)/2 Check: [(3 + i√599)/2][(3 - i√599)/2] = [32 - (i√599)2]/4 = (9 - 599i2)/4 =( 9 + 599)/4 = 608/4 = 152 (3 + i√599)/2 + (3 - i√599)/2 = (3 + i√599 + 3 - i√599)/2 = 6/2 = 3
599
yes 599 is prime
0
Yes - 599 is an integer.