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How do you rewrite an equation in function form?
lets say you have to write 5x+6y=-12 in function form. when you are writing an equation in function form, you usually solve for f(x) or g(x), but in this case, y is the same as f(x) or g(x). so to write 5x+6y=-12 in function form, you do this: 5x+6y=-12 6y= -5x -12 subtract 5x from both sides y= -5/6x -2 divide both sides by 6
How do you re-write x squared plus 5x - 3 in vertex form?
8
How do you write 5x - 10y equals 3 in slope intercept form?
y = 0.5x - 0.3
What us 5x-y equals 8 in slope intercept form?
-3
How do you Write the equation for 5x plus 2y 3 in slope-intercept form.?
To write the equation (5x + 2y = 3) in slope-intercept form (y = mx + b), first isolate (y). Subtract (5x) from both sides to get (2y = -5x + 3). Then, divide each term by 2 to solve for (y): (y = -\frac{5}{2}x + \frac{3}{2}). Thus, the equation in slope-intercept form is (y = -\frac{5}{2}x + \frac{3}{2}).
How do you rewrite an equation in function form?
lets say you have to write 5x+6y=-12 in function form. when you are writing an equation in function form, you usually solve for f(x) or g(x), but in this case, y is the same as f(x) or g(x). so to write 5x+6y=-12 in function form, you do this: 5x+6y=-12 6y= -5x -12 subtract 5x from both sides y= -5/6x -2 divide both sides by 6
How do you rewrite 5x plus 5y equals 19 in function form?
5x + 5y = 19x = 3.8 - yory = 3.8 - x
How do you write 5x-y equals 8 in slope-intercept form?
-3
How do you re-write x squared plus 5x - 3 in vertex form?
8
How do you write 5x - 10y equals 3 in slope intercept form?
y = 0.5x - 0.3
Why are linear equation named linear equation?
Y = 5X - 3It form a linear function; a line.
What us 5x-y equals 8 in slope intercept form?
-3
Is x2 plus 5x a function?
No. x2+5x is a polynomial, an algebraic expression or a formula, but it is not a function. It could be used to help define a function. {(x,y) | y = x2 + 5x , x any real number} is a function
How do you Write the equation for 5x plus 2y 3 in slope-intercept form.?
To write the equation (5x + 2y = 3) in slope-intercept form (y = mx + b), first isolate (y). Subtract (5x) from both sides to get (2y = -5x + 3). Then, divide each term by 2 to solve for (y): (y = -\frac{5}{2}x + \frac{3}{2}). Thus, the equation in slope-intercept form is (y = -\frac{5}{2}x + \frac{3}{2}).
How do you find the numbers x-intercepts of function y equals 5x'2?
5x²=0 X=0 the function y=5x² only intercepts x when x = 0
Which function is the inverse function of y 5x - 4?
1
Write the equation in slope-intercept form of the line that has a slope of -5 and a y-intercept of 2?
-7
