8
The vertex is at the point (0, 4).
(-3, -5)
The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.
(x + 5)2
The vertex of the positive parabola turns at point (-2, -11)
The vertex is at the point (0, 4).
(-3, -5)
Y = X2 + 6X + 2set to 0X2 + 6X + 2 = 0X2 + 6X = - 2now, halve the linear coefficient ( 6 ), square it and add it to both sidesX2 + 6X + 9 = - 2 + 9gather terms on the right and factor the left(X + 3)2 = 7(X + 3)2 - 7 = 0==============vertex form(- 3, - 7)=======vertex
The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.
(x + 5)2
The vertex of the positive parabola turns at point (-2, -11)
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
The equation you gave, 2y+5 = (x-4)2 can also be expressed as y = 0.5(x-4)2 - 5. In the form a(x-p)2 + q, the vertex is the point (p, q). Thus, the vertex of 2y + 5 = (x-4)2 is (4, -5).
104
23
The vertex is (-9, -62).
To factor this, find two numbers whose product is 81 and sum 18. These two numbers are therefore 9 and 9. So we can rewrite the polynomial in its factored form as follows: (k+9)(k+9), or "k plus 9 squared"