3*(n - 5) = 2*n + 11
13 < 2n - 5 < 21
2n - 2
2x-3
2k - 7
3a-6x2
32 - 2x < 18
twice a number can be 2x and six less than it is 2x-6.
To write out the given statement algebraically, you would start by defining the variable for the number, let's say it is represented by 'x'. The equation would be: 6x - 5 < 2x + 10. This equation represents the statement "Six times a number minus five is less than twice the number plus ten" in algebraic form. To solve this inequality, you would isolate the variable 'x' by performing operations to simplify and find the range of values that satisfy the inequality.
Let the number be x Twice a number means 2x 7 less than twice a number means 2x-7
the quotient of twice a number and six is.... 2x/6 four less than three times the same number is .... 3x-4 So the equation would be 2x/6=3x-4
If the number is n then twice the number is 2n and 7 less than twice the number is 2n - 7This could also be a boolean variable based on another variable. If the number is less than or equal to 3.5, the variable is false. Otherwise, it is true.
3*(n - 5) = 2*n + 11
13 < 2n - 5 < 21
One less than twice a number = (X times 2) minus 1, (where X = your number of choice).
If the number is 'z', then five less than twice the number is ( 2z - 5 ).
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