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No. It refers to quadratic equations of the form (x + n)2 = c where n and c are real values. "Completing the square" solves for values of the x-intercepts (y=0). (see the related link)
It solves a system of equations. Think of the 2X2 case of having X+Y=1 and 3X+2Y=6.
The person or program that solves the equation does.
I see something like this and I use the quadratic formula, which solves all quadratic equations. Discriminant, by inspection, looks good for two real roots. X = -b +/- sqrt(b^2 - 4ac)/2a a = -3 b = -1 c = 2 X = -(-1) +/- sqrt[(-1)^2 - 4(-3)(2)]/2(-3) X = 1 +/- sqrt(25)/-6 X = {1 +/- 5}/-6 X = -1 X = 2/3 My TI-84 confirms these values for X
A polymath.