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I see something like this and I use the quadratic formula, which solves all quadratic equations. Discriminant, by inspection, looks good for two real roots.

X = -b +/- sqrt(b^2 - 4ac)/2a

a = -3

b = -1

c = 2

X = -(-1) +/- sqrt[(-1)^2 - 4(-3)(2)]/2(-3)

X = 1 +/- sqrt(25)/-6

X = {1 +/- 5}/-6

X = -1

X = 2/3

My TI-84 confirms these values for X

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14y ago

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Q: How do you solve -3x2 - x plus 2 equals 0?
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