I would do it that way.
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
You cannot because 50 is an integer with an absolute value which is greater than 1. It is not a fraction.
well u do stuff to figure it out
You can add or subtract the same number to both sides of an equation without changing the solution, so adding 4 to both sides yields |5x| = 20. Since 5 is positive, it can be moved outside the absolute value: 5*|x| = 20. You can multiply or divide both sides of the equation by any non-zero number, so you can divide both sides by 5 to get |x| = 4.So x is either 4 or -4, will solve your equation. If you want to write the equation without using absolute value, you can write a quadratic equation which has solutions of 4 and -4: (x + 4)(x - 4) = 0 --> x² - 16 = 0
In order to write f(x) = |x| + |x-2| without the absolute value signs, it it necessary to write it as a piecewise function.We must define f as follows:f(x) = -2x + 2, if x < 0f(x) = 2, if 0
write two numbers that have the given absolute value. 1.4
I would do it that way.
No, because it's absolute value is less than 1.
Travis Quaterman
The expression (a+b) + (a-b) can be rewritten as a + b + a - b = 2a.There is no need to use absolute value.
EX: y=|2x+4| EX: z= -|4s^2|
4
b<= 98.7 + l 2 l
Negative numbers are integers as well. The absolute value of any negative integer will be positive and therefore larger than itself.
I'm pretty sure the answer is negative 11
513/7 = (490+23)/7 = 490/7 + 23/7 = 70 23/7 is the mixed number. 75.8571429 is the absolute value of 523/7