NO! abs(2-2)=0 NOT equal to abs(2)+abs(-2)=4 - The above is technically correct, though the more thorough answer is as follows; no because the absolute value of the sum is LESS THEN OR EQUAL TO the sum of the absolute values. The simple proof the the fact that |A+B|<=|A|+|B| is called the triangular inequality. When A and B (or for that matter an infinite number of them) are both positive (or all) or both negative (or all) then they inequality is actually equal, if however any of the numbers have different signs then any other number, the inequality is less then.
Chicken nuggets to a high degree of intolerance, but tainted with Mrs. Acevedo's long-term sub who will destroy those who drank Arizona Green Tea in class.
That is called the "absolute value" of the number. For example:The absolute value of 5 is 5.The absolute value of -5 is also 5.That is called the "absolute value" of the number. For example:The absolute value of 5 is 5.The absolute value of -5 is also 5.That is called the "absolute value" of the number. For example:The absolute value of 5 is 5.The absolute value of -5 is also 5.That is called the "absolute value" of the number. For example:The absolute value of 5 is 5.The absolute value of -5 is also 5.
no number; absolute value is always positive. The absolute value of a negative number is positive. For example absolute value of -4 is +4
The absolute value of 19 is 19. If x is positive , absolute x equals x.
It is an equation used to anwer an absolute value inequality.
b<= 98.7 + l 2 l
well u do stuff to figure it out
What's your question? To solve an absolute value inequality, knowledge of absolute values and solving inequalities are necessary. Absolute value inequalities can have one or two variables.
If the absolute value inequality is of the form where the absolute value of the difference between a variable (X) and some constant (a) is compared to another constant (b) eg |X - a| compared with b, then if the comparison is < or ≤, the compound inequality is a double inequality of the form c < X < d (or ≤), and if the comparison is > or ≥, the compound inequality is a disjoint inequality of the form X < c or X > d (or including the equals). In both cases, c = b - a, d = b + a (>c)
mamadjf
write two numbers that have the given absolute value. 1.4
There are many possible answers but the simplest is |x + 2| = 8
|x|=√(x^2).
perimeter of a rectangle = 96m w = 3 + 0.5L what is W and L? (answer: 18 and 30)
Good question.Think about lxl > 3: x can be >3 or goes with or. < goes with and.
Do you mean 3 + 4|3x + 7| ≤ - 89? There is no solution to the inequality, since it is a false statement. A positive number cannot be equal or less than a negative number. On the left side, you are dealing only with positive numbers, since the absolute value is always positive, no matter what the values of x are.