Q: How do you write an equation for a circle graph with center at (-42) and radius 5?

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x2 + y2 = r2 gives a circle centred on the origin, radius r.

The graph of that equation is a circle, centered at the origin, with radius = 2 .

there is actually multiple ways to do this. the easiest way is to use this formula (x - h)² + (y - k)² = r² r is the radius, h is the x-poss( how far left or right the center of the circle is from the orgin), k is the y-poss(how far up or down the circle is). keep x and y as x and y just like you will do when graphing a line using y = mx + b example: (x - 3)2 + (y - k)2 = 25 note: not all graphing calculators can graph a circle. mine will graph half a circle instead. this websight has a hands on circle graph that you can test out, it also has practice problems: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php for more advanced users, you can graph a circle using polar cordinates instead. if you don't know what these are, you don't have to worry about this. to graph a circle using polar cordinants use this orderd pair (radius,theta) and make the the radius whatever you want the radius of the circle to be. keep theta as theta, if you make this a number you will graph a point. this will make a circle with it's center on the organ. example: (3,theta)

Circles have the general equation (x-h)2 + (y-k)2 = r2 where (h,k) will be the center of the circle on a graph and r is its radius. If the circle is centered at the origin h=k=0 and the equation simplifies into x2 + y2 = r2 'Solving' implies that you know certain conditions. You substitute those into the appropriate equation and solve for the unknown.

If you want to have an center point of zero you use the equation x2+y2=r2. In this case x2+y2=9.

Related questions

Equation of a circle when its centre is at (0, 0): x^2 + y^2 = radius^2 Equation of a circle when its centre is at (a, b): (x-a)^2 + (y-b)^2 = radius^2

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

x2 + y2 = r2 gives a circle centred on the origin, radius r.

The graph of that equation is a circle, centered at the origin, with radius = 2 .

It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).

Draw a circle with its center at the origin and a radius of 3.

there is actually multiple ways to do this. the easiest way is to use this formula (x - h)² + (y - k)² = r² r is the radius, h is the x-poss( how far left or right the center of the circle is from the orgin), k is the y-poss(how far up or down the circle is). keep x and y as x and y just like you will do when graphing a line using y = mx + b example: (x - 3)2 + (y - k)2 = 25 note: not all graphing calculators can graph a circle. mine will graph half a circle instead. this websight has a hands on circle graph that you can test out, it also has practice problems: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php for more advanced users, you can graph a circle using polar cordinates instead. if you don't know what these are, you don't have to worry about this. to graph a circle using polar cordinants use this orderd pair (radius,theta) and make the the radius whatever you want the radius of the circle to be. keep theta as theta, if you make this a number you will graph a point. this will make a circle with it's center on the organ. example: (3,theta)

Circles have the general equation (x-h)2 + (y-k)2 = r2 where (h,k) will be the center of the circle on a graph and r is its radius. If the circle is centered at the origin h=k=0 and the equation simplifies into x2 + y2 = r2 'Solving' implies that you know certain conditions. You substitute those into the appropriate equation and solve for the unknown.

There are two common ways to graph circles: using a cartesian graph and using a polar graph. For a cartesian graph, there are two familiar axes x and y which are orthogonal to each other. The formula for a circle is "x^2 + y^2 = a constant". In a polar graph, there are no axes and all points are defined by their radius from the center point, and the angle of the direction the point lies from the center. In a polar coordinate system, a circle is simply "r = a constant".

The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25

Any point on the graph can be the center of a circle. If the center is on the x-axis, then the circle is symmetric with respect to the x-axis.

It is a graph of all points which are are the same distance (the radius) from a fixed point (the centre).