Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
To find the y-intercept of a line with a given slope and a point it passes through, you can use the slope-intercept form of a line, which is (y = mx + b), where (m) is the slope and (b) is the y-intercept. Substitute the coordinates of the given point and the slope into the equation to solve for (b). Rearranging the equation will yield the value of the y-intercept. Without specific numerical values for the slope and point, I can't provide a numerical answer, but this is the method to find it.
Y=mc+b
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
The equation is x = -7.
A straight line in slope-intercept format has the equation: y = mx + b Where m is the slope, b the y-intercept. So, all you have to do is copy this equation, then replace "m" by the given slope, and "b" by the given y-intercept.
no it is different
To find the y-intercept of a line with a given slope and a point it passes through, you can use the slope-intercept form of a line, which is (y = mx + b), where (m) is the slope and (b) is the y-intercept. Substitute the coordinates of the given point and the slope into the equation to solve for (b). Rearranging the equation will yield the value of the y-intercept. Without specific numerical values for the slope and point, I can't provide a numerical answer, but this is the method to find it.
True ~APEX
Y=mc+b
An equation in slope intercept form is given by y = mx + b, where m is the slope and b is the y-intercept.Examples:If the slope is 3 and the y- intercept is 4, the equation will be, y = 3x + 4If the slope is -1/5 and y-intercept is -2/3, the equation will be, y = -1/2)x - 2/3
y = mx + b, where m is the slope and b is the y-intercept.