12
g(x) = x/2
Yes.
f(x)=2x+2. Put in 0, 1/2, 1, 3/2, 2... and you will get integer values. That is for the domain. The numbers you get when you put that in are the range integral values.
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
2+0.0+0.08+0.009
12
What_is_the_area_bounded_by_the_graphs_of_fx_and_gx_where_fx_equals_xcubed_and_gx_equals_2x-xsquared
g(x) = x/2
5x lolzz 8)
f(x) = √(2x -3) f(x) = (2x - 3)^(1/2) f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2) f'(x) = (2x - 3)^(-1/2) f'(x) = 1/[(2x - 3)^(1/2)] f'(x) = 1/√(2x -3)
True
f(x) is the same thing as y= example: f(x)=2x+3 OR y=2x+3
please elaborate your question
NO
y = 3x + 2x^2 + k where k is any number
u can't