6*(x + 7)
6(x+12)
Six times three equals eighteen. Subtracting twenty-four leaves your sum at negative six.
To write twice the sum of a number and 600, you first express the number as a variable, such as ( x ). The sum of the number and 600 can be written as ( x + 600 ). Therefore, twice this sum is represented as ( 2(x + 600) ).
To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps: Initialize a variable sum to 0. Loop five times to accept input for each number, adding each to sum. After the loop, calculate the average by dividing sum by 5. Display both the sum and the average. Here’s a simple representation: BEGIN sum = 0 FOR i FROM 1 TO 5 DO INPUT number sum = sum + number END FOR average = sum / 5 OUTPUT "Sum: ", sum OUTPUT "Average: ", average END
if the sum of three is six then it would be 30 right?? i think depends on wat sum of 3 is
6(x+12)
Write the following as an algebraic expression using x as the variable: The sum of a number and -8
7x +9 = 6x
the product of 8 and the sum of 10 and -7
3(z+15)
Six times three equals eighteen. Subtracting twenty-four leaves your sum at negative six.
six times the sum of eight and eight 6*(8+8) = 96add eight to eight and multiply the result by six.
To write twice the sum of a number and 600, you first express the number as a variable, such as ( x ). The sum of the number and 600 can be written as ( x + 600 ). Therefore, twice this sum is represented as ( 2(x + 600) ).
The sum is 728
17x+(1+x)
x + 138
sum = 2n + 3m