You can only do so if the coordinate pair is other than the x intercept.
Suppose the x intercept is A = (a, 0) and suppose the coordinate pair is R = (s, t)
Then gradient = (t-0)/(s-a) = t/(s-a)
Suppose P = (x, y) are the coordinates of any point on the line. Then gradient of PA = (y-0)/(x-a) = y/(x-a)
The two gradients must be the same so t/(s-a) = y/(x-a)
or y*(s-a) = t*(x-a)
or y = t/(s-a)*x - ta/(s-a) which is of the form y = mx + c
with m = t/(s-a)
and c = -ta(/(s-a)
It is the locus of all points whose coordinates satisfy the equation of the line.
By substitution
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
Subtract the equation of one line from the equation of the other
Substitute the coordinates of the point into the equation of the line. If the result is true, then the point is on the line.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
-5
Since the slope of the line is 0, then the line is a horizontal line, and since the y-coordinates of the two points are 0, then the line lies on the x-axis. Thus, the equation of the line is y = 0.
It is the locus of all points whose coordinates satisfy the equation of the line.
Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
By substitution
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
Subtract the equation of one line from the equation of the other
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
Substitute the coordinates of the point into the equation of the line. If the result is true, then the point is on the line.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
Assume the equation is y = kx + c Put in the x and y values of your known coordinates and sove the simultaneous equations.