The algebraic expression is n + 100, where n is the unknown number.
100
sum= answer of an addition question.. so the number of the sum is the answer.
101
write the number that is 100 less
If the first number is 100 then the second number is 50 and the sum is 150. If the second number is 100 then the first number is 200 and the sum is 300. The question cannot be answered with one solution as it is currently worded.
100
sum= answer of an addition question.. so the number of the sum is the answer.
101
The sum of the first 100 counting numbers (1-100) is 5,001.
write the number that is 100 less
The sum of the first 100 natural numbers is 5,001.
int i, sum; /* example using while */ sum = 0; i = 1; while (i <= 100) { sum += i; ++i; } /* example using for */ sum = 0; for (i = 1; i <= 100; ++i) sum += i;
Write a program to find the number and sum of all integers from 100 to 300 that are divisible by 11
a+21
class sum { void main () { int sum = 0; int n = 1; while ( n <= 100 ) { sum = sum + n; n++ ; } System.out.println("Sum is = " + sum ); }}
If the first number is 100 then the second number is 50 and the sum is 150. If the second number is 100 then the first number is 200 and the sum is 300. The question cannot be answered with one solution as it is currently worded.
Oh, isn't that just lovely? To express the sum of a number and ten in mathematical terms, you simply write it as "x + 10" where 'x' represents the number you're adding ten to. Just imagine that number and ten dancing together on the canvas of mathematics, creating a beautiful harmony of addition. Happy little numbers!