The sum of the first 100 natural numbers is 5,001.
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Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
The sum of the first 100 numbers, excluding zero, is 5,001.
s100=50(2+99) this is because a=1, d=1 and n=100. answer is 5050
The answer is 3