Study guides

☆☆

Q: What is the sum of the first 100 natural number?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050

sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275

The sum of the first 100 numbers, excluding zero, is 5,001.

s100=50(2+99) this is because a=1, d=1 and n=100. answer is 5050

The answer is 3

Related questions

#includeint main(){int i,sum=0;for(i=1;i

The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.

The sum of the first 57 natural numbers is 1,625.

The sum of the first 100 counting numbers (1-100) is 5,001.

The sum of the first 10 natural numbers is 51.

If the first number is 100 then the second number is 50 and the sum is 150. If the second number is 100 then the first number is 200 and the sum is 300. The question cannot be answered with one solution as it is currently worded.

Find the sum of the first hundred even natural number divisible by 5?

The sum of 2 and 97 is 99.

#include<stdio.h> #include<conio.h> void main() { int n; printf("Enter any number"); scanf("%d",&n); sum=((n*(n+1))/2); printf("The sum of first 100 natural numbers is\t%d",sum); }

The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.

This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.

Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050

People also asked