How do you write x3 plus 2x2-5x-6 in factored form?

Answer 1

x3 + 2x2 - 5x - 6 = x3 + x2 + x2 + x - 6x - 6 = x2(x + 1) + x(x + 1) - 6(x + 1)

= (x + 1)(x2 + x - 6) = (x + 1)(x2 + 3x - 2x - 6) = (x + 1)[x(x + 3) - 2(x + 3)]

= (x + 1)(x + 3)(x - 2)