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(x^2 + 7)(x^2 + 2)

Q: How do you completely factor x to the fourth power add 9x square add 14?

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It is: (x-y)4

(x2 + 1)(x2 - 2)

X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.

A biquadrate is a fourth power of a number, the square of a square.

(x^2 - 3x + 5)(x^2 + 3x + 5)

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It is: (x-y)4

(x2 + 1)(x2 - 2)

x^2(x - 4)(x + 4)

X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.

(x^2 - 3x + 5)(x^2 + 3x + 5)

A biquadrate is a fourth power of a number, the square of a square.

2x to the fourth power minus 162 equals -146

(3x^2 - 4y^2)(3x^2 + 4y^2)

sqrt of the fourth power = square So the answer is (50x)2 = 2500x2

The square of a number would be the fourth power of the square root of the number.

It is +1

Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).