23
(x^2 + 7)(x^2 + 2)
It is: (x-y)4
(x2 + 1)(x2 - 2)
X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.
A biquadrate is a fourth power of a number, the square of a square.
(x^2 - 3x + 5)(x^2 + 3x + 5)
It is: (x-y)4
(x2 + 1)(x2 - 2)
x^2(x - 4)(x + 4)
X4 - 144 (X2 - 12)(X2 + 12) As there is no linear term I see no further factoring.
(x^2 - 3x + 5)(x^2 + 3x + 5)
A biquadrate is a fourth power of a number, the square of a square.
2x to the fourth power minus 162 equals -146
(3x^2 - 4y^2)(3x^2 + 4y^2)
sqrt of the fourth power = square So the answer is (50x)2 = 2500x2
The square of a number would be the fourth power of the square root of the number.
It is +1
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).