Mathematical (programmatic) explanation of rounding to base
Number (n)
Base (b)
Modular (m) = n Mod b
Pure Number (np) = n - m
if m/b is more than or equal to 0.5 then np = np+b
Solution
n = 4141.07
b = 10
m = 4141.07 Mod 10 = 1.07
np = 4141.07 - 1.07 = 4140
if 1.07/10 is more than or equal to 0.5 then np = 4140+10
The answer is np = 4140
Explanation
Using the mathematical approach to round a number is not necessary, but is an efficient way to explain how it works.
A faster method would simply be to look at the base you're trying to round to. In this case, the 4 tens in 4141.07, the subsequent number must be more than or equal to half of your base, otherwise it is rounded back to 4 tens. If it is more than or equal to half of your base you would add another ten, giving a rounded number of 4150. Since we have the base 10, and the subsequent number after our tens are 1.07, and 1.07 is less than 5 (base/half) we round down to 40
4.4, to the nearest tenth.
It is 9.5 rounded to the nearest tenth
73.19, to the nearest tenth, is 73.2
158.097 to nearest tenth = 158.1
It is already rounded to the nearest tenth.
round 48.6 to the nearest tenth
Round 3.7416573 to the nearest tenth is 3.7
To the nearest tenth it is 2796.
118.0
It then is 471.4 to the nearest tenth
It is 61.9 to the nearest tenth
It then is 0.7 to the nearest tenth
It is 263.8 to the nearest tenth
4.4, to the nearest tenth.
24.6 Round 24.583 to the nearest tenth? => 24.600
It then is 1.5 when rounded to the nearest tenth
It is 64.2 when rounded to the nearest tenth