A = HL 1*24 2*12 3*8 4*6
24
6 and 2
6(7 - (2 + 1)) = 24 2 plus 1 equals 3. 7 minus 3 equals 4. 4 times 6 equals 24.
(2*6)+8+4 = 24
Pairs of integers which when multiplied equal -24 are: -3 8 -4 6 -6 4 -12 2 -24 1 3 -8 4 -6 6 -4 12 -2 24 -1
6 * [5-(2-1)] = 6*[5-1] = 6*4 = 24
No. Convert to equivalent fractions with the same denominator and compare numerators: 4/8 = (4×3)/(8×3) = 12/24 2/6 = (2×4)/(6×4) = 8/24 12 does not equal 8, so 12/24 does not equal 8/24, thus 4/8 does not equal 2/6.
add 2+5+6+6+2+4 which equals 24.but you get the 2 and 4 from the 24 that's in the problem.
1 * 24 = 24 2 * 12 = 24 3 * 8 = 24 4 * 6 = 24
They are: 6 and 4 or 8 and 2
A = HL 1*24 2*12 3*8 4*6
4 * (-4 + 5) * 6 = 24.
24 divided by 6 is 4.
24
If it's:p^2 - 2p - 24 =0Then Factorise:p^2 - 2p - 24 = 0(p - 6)(p + 4) = 0Therefore:(p - 6) = 0 OR (p + 4) = 0p = 6 OR p = -4Answer: p = 6 or -4
It is equal to: 20v^2 +4v -24