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A point represents an infinitesimally small area in space. In the case of a line graph, and assuming the point is on the line, it represents the exact value of the linear function of x, f(x) or y, at any given value of x. The important thing to remember is that when you actually draw a dot on a graph representing a point, you're really representing an object with no dimensions.
Without an equality sign the given expression can't represent the graph of a straight line equation.
The gradient (slope) of the tangent to the graph at the given time - provided that it exists. If the graph is a straight line at that point, it is the gradient of that line.
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.