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A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)
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How fast would you fall from a 60 foot cliff?
Depending on whether or not you got a running start (this affects your body's velocity) you would be falling between 40 and 45 mph.
How do you find vertical velocity and vertical distance?
The answer will depend on the conditions under which the body is moving and how sophisticated your calculations need to be. On (or near) the surface of the earth, if the body had velocity v0 ms-1 at time t0 seconds then in the simple model, its velocity at time t seconds will be v = v0 - 9.81*t ms-1 (approx). The vertical distance will be v0t - 9.81t2 metres. In a more sophisticated model you would include air resistance. Also if v0 is large, it is possible that the height attained is large enough to affect deceleration due to gravity.
What is variable velocity?
variable velocity can be defined as a moving body whose velocity changes with time
Can the average velocity of a body be the same as the instateneous velocity?
Yes, But in uniform motion only.
Can the average velocity of the body be the same as instantaneous velocity?
Yes, the average velocity of the body can be same as the instantaneous velocity at a small time interval.The values of the average and the instantaneous velocities approach each other , as the length of time interval is decreased.
