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A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)

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Q: How does height affect the velocity of a falling body?
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Related questions

What is the relationship of height of a free falling object in terms of final velocity and its time of fall?

The height where from the body is dropped ie h is given as h = v2 / 2g and h = (1/2) g t2 v is the final velocity and t is time of falling g = acceleration due to gravity


What kind of energy is in a falling object?

Kinetic energy of a falling object can be calculated for a specific height at a specific point since a falling body accelerates which means that it's velocity is changing every moment. To calculate the kinetic energy of a falling body at a certain height, we should know the mass of the body and its velocity at that point.Then we can apply the following formula: K.E. of an object = 1/2(mv2)


A body falling freely from a height towared the earth moves with uniform?

... accelerates at approx 9.81 metres per second squared and experiences weightlessness. Friction with the air prevents continuous acceleration and the falling body reaches a maximum velocity called the terminal velocity.


Does the Magnitude of a charge affect the velocity of body?

No, the magnitude of a charge does not directly affect the velocity of a body. The velocity of a body depends on the forces acting on it, such as electromagnetic forces, gravitational forces, or friction. The charge of a body affects how it interacts with electric and magnetic fields, but it does not affect its velocity directly.


Can a object falling from a height be in equilibrium in mid air?

Yes. An object is in equilibrium if the velocity is constant. A constant velocity can occur if the forces balance on the object. Consider that the gravitational force is balanced by the "air resistance force", then there is no net force and thus no acceleration. Then the velocity at which this occurs will be a constant and thus the body will be in equilibrium.


Are the directions of the velocity and acceleration of a falling body the same?

Yes, both are directed downward.


Are the direction of the velocity and acceleration of a falling body the same?

For the most part, yes; once at terminal velocity, there is no acceleration, so it has direction.


Are the directions of the velocity and acceleration of a falling body they same?

Yes, as long as gravity is the only force acting on the body.


What changes in a freely falling body?

In a freely falling body, its velocity increases due to the acceleration caused by gravity. The acceleration is constant (9.8 m/s^2 on Earth), and the body's motion is only affected by gravity, not air resistance. The body's position changes continuously as it falls towards the ground.


What is the graph of the motion of a body falling vertically that reaches a terminal speed?

The graph of the motion of a body falling vertically that reaches a terminal speed would show an initial acceleration until the body reaches its terminal velocity. At this point, the graph would level off, showing constant velocity as the body falls continuously.


Velocity time graph for a body dropped from a certain height?

The velocity-time graph for a body dropped from a certain height would show an initial spike in velocity as the object accelerates due to gravity, reaching a maximum velocity when air resistance equals the force of gravity. After this, the velocity would remain constant, representing free fall with a terminal velocity. When the object hits the ground, the velocity suddenly drops to zero.


The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?

The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.