The answer will depend on the conditions under which the body is moving and how sophisticated your calculations need to be.
On (or near) the surface of the earth, if the body had velocity v0 ms-1 at time t0 seconds then in the simple model, its velocity at time t seconds will be v = v0 - 9.81*t ms-1 (approx). The vertical distance will be v0t - 9.81t2 metres. In a more sophisticated model you would include air resistance. Also if v0 is large, it is possible that the height attained is large enough to affect deceleration due to gravity.
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Simple, velocity = distance by time ,which probably means distance = velocity X times.
Distance divided by velocity = time
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
Decrease ..
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).