A jogger travels at a speed of 5 miles and seconds for a minute. How far would he or she travel in that time
If it's moving at 70 meters per second, and it's moving for 5 seconds..Simple math. 70 x 5 = 350 meters in 5 seconds.
45 mph = 45 miles/hour (45 miles/hour) (1hr/60 minutes) (1 minutes/60 seconds) (5 seconds) = 0.0625 miles in 5 seconds Note: If you write the fractions above with a horizontal slash instead of a diagonal slash, it is easier to see what cancels out to make this problem work the way it does.
To determine how far each rider will travel in five seconds, we need their speed. If we know the speed of each rider in meters per second, we can multiply that speed by five seconds. For example, if a rider travels at 10 meters per second, they will cover 50 meters in five seconds (10 m/s × 5 s = 50 m). Without specific speed information, we cannot calculate the distance traveled.
5 miles
A jogger travels at a speed of 5 miles and seconds for a minute. How far would he or she travel in that time
Speed of light 3.0*10^8 m/s times 5 seconds = 15*10^8m
25 mile in one hour one hour has 60*60 = 3600 seconds Therefore distance travelled in 5 seconds = (25/3600)*5= 0.0347222222222222 miles.
Simply multiplication - 1.25km !
A car can go up to 75 mph in 5 seconds Answer - At 60 MPH you would travel 88 feet per second. 5 x 88 = 440 feet in five seconds.
The biker travels 10 feet in 1 second (since 5 feet in 0.5 seconds). In 1 minute, there are 60 seconds, so the biker will travel 60 x 10 = 600 feet in 1 minute.
Light travels at 186600 mps in vacuo. This means that in 5 seconds the light from a laser would travel 186600 * 5= 933000 miles away/
If it's moving at 70 meters per second, and it's moving for 5 seconds..Simple math. 70 x 5 = 350 meters in 5 seconds.
514.28 seconds.
Distance = speed x time. However, no car will move that fast.
45 mph = 45 miles/hour (45 miles/hour) (1hr/60 minutes) (1 minutes/60 seconds) (5 seconds) = 0.0625 miles in 5 seconds Note: If you write the fractions above with a horizontal slash instead of a diagonal slash, it is easier to see what cancels out to make this problem work the way it does.
To determine how far each rider will travel in five seconds, we need their speed. If we know the speed of each rider in meters per second, we can multiply that speed by five seconds. For example, if a rider travels at 10 meters per second, they will cover 50 meters in five seconds (10 m/s × 5 s = 50 m). Without specific speed information, we cannot calculate the distance traveled.