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What would be the change in velocity for a 10 gram object dropped from the roof of a 20 meter building if it takes 2 seconds to reach the ground Hint acceleration due to gravity is 98 ms²?
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
How far does a plane fly in 15 seconds while its velocity is increasing from 75 meters per second to 145 meters per second at a uniform rate of acceleration?
Use this equation.... x= x0 + V0*t + a*t^2 x0 = 0 v0 = 75 m/s a = (145-75)/15 = 4.67 m/s^2 t = 15 s x = 0 + 75 m/s * 15s + 4.67 m/s^2 *15^2 x = 2176 m
How far does a plane fly in 15 s while its velocity is changing from 145 to 73 at a uniform rate of acceleration?
Since the acceleration is uniform you can add the starting and ending velocities and divide by two the average speed 145 + 73 = 218 218/2 = 109 (units not given so I assume Miles per Hour) To convert to Feet per seconds 109 mph X 5280 feet in a mile / 3600 seconds in an hour = 159.866667 feet per second multiply the above by 15 seconds and you get 2398 feet
How many feet in one sec?
Feet refers to a distance while seconds is time, so you can't say that there are a certain number of feet in one second. You can however say that you travel a certain number of feet in one second, but that number depends on the velocity that you are traveling at.
Are the wedge and inclined plane the same thing?
While a wedge and an inclined plane are not the same things, a wedge is a type of inclined plane. However, not all inclined planes are considered to be wedges.
How far does a plane fly in 15 seconds while it's velocity is increasing from 75 m s to 145 m s at a uniform rate of acceleration?
To calculate the distance traveled while the velocity is increasing, you can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, the initial velocity is 75 m/s, the final velocity is 145 m/s, the acceleration is constant, and the time is 15 seconds. Plugging these values into the formula will give you the distance the plane travels during the acceleration period.
How far does a plane fly in 15 seconds while its velocity is increasing from 75 ms to 145 ms at a uniform rate of acceleration?
To find the distance the plane travels, you can use the average velocity formula, which is the sum of initial velocity and final velocity divided by 2, and then multiply by the time. Average velocity = (75 m/s + 145 m/s) / 2 = 110 m/s Distance traveled = (110 m/s) * 15 s = 1650 meters
How far does a plane fly in 15 seconds while its velocity is increasing from 75 miles per second to 145 miles per second at a uniform rate of acceleration?
To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. The initial velocity is 75 miles per second, the final velocity is 145 miles per second, and the time is 15 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time. Plug in the values to find the acceleration and then calculate the distance traveled in 15 seconds.
How can the momentum of a body be increase?
The momentum of a body can be increased by either increasing its mass or its velocity. Increasing the mass of the body will increase its momentum, while increasing the velocity of the body will also increase its momentum as momentum is calculated as mass times velocity.
What is the difference between increasing velocity and uniform velocity?
Increasing velocity means the speed of an object is getting faster over time, while uniform velocity means the speed of an object remains constant. In other words, increasing velocity involves acceleration, while uniform velocity does not.
Does increasing the mass or velocity have the most affect on an object's kinetic energy?
Increasing an object's velocity has a greater effect on its kinetic energy than increasing its mass. This is because kinetic energy is directly proportional to the square of the object's velocity, while it is linearly proportional to the object's mass.
How fardoes a plane fly in 15 seconds while its velocity is increasing from 75ms to 145ms at a uniform rate of acceleration?
Well, first you solve for acceleration using "a= (Vf-Vi)/t" a= (Vf-Vi)/t a=(145-75)/15 a=70/15 a=14/3 m/s2 Then you can use "d=vit+1/2at2" to solve for distance d=vit+1/2at2 d=(75)(15)+1/2(14/3)(15)2 d=1125 + 525 d=1650m And there's your answer. ---- Alternatively, you could use d=t(vi+vf)/2 d=t(vi+vf)/2 d=15(75+145)/2 d=1650m
Which term explains whether an object's velocity has increased and decreased over time?
Acceleration is the term that explains whether an object's velocity has increased or decreased over time. Positive acceleration indicates velocity is increasing, while negative acceleration indicates velocity is decreasing.
What is average radial velocity of Mars?
The average radial velocity of Mars is 1.85° that is inclined to the ecliptic. While its inclination to the Sunâ??s equator 5.65° and its inclination to an invariable plane is 1.67°.
What are some factors that affect Kinetic Energy?
The main factors that affect kinetic energy are mass and velocity of an object. Increasing the mass of an object will increase its kinetic energy, while increasing the velocity of an object will increase its kinetic energy even more significantly. The formula for kinetic energy is KE = 0.5 * mass * velocity^2.
What is the only factor that affects the range of a projectile?
The initial velocity of the projectile is the only factor that affects its range. Increasing the initial velocity will result in a longer range, while decreasing it will result in a shorter range.
What is the difference bet increasing acceleration and increasing deceleration?
Increasing acceleration refers to an increase in the rate at which an object speeds up, while increasing deceleration refers to an increase in the rate at which an object slows down. Acceleration results in a higher velocity, while deceleration results in a lower velocity.
