0
What quantity is represented by the slope of a velocity time graph?
Wiki User
∙ 8y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
Which physical quantity is calculated by the slope of distance time graph?
The radial velocity ie velocity towards or away from your starting point. It is NOT the ordinary speed or velocity because you can run in a circle around your starting point at top speed but the distance will not change so the slope of the distance time graph will be zero.
How do you calculate velocity from an x-t graph?
If an x-t graph is a position-time graph, velocity is the slope of the line on the graph.
Why does the slope of a velocity time graph give you acceleration?
if there is a slope, the velocity is either increasing or decreasing. This is acceleration.
What is the physical property represented by the slope of a distance time graph?
The velocity. To convince yourself, consider the units of the slope. Slope = rise/run = vertical/horizontal= distance/time=units of velocity. Alternately, consider the meaning of the graph. Where the slope is high, the distance is changing fast over a small time - high velocity.
The slope of a position- time graph?
It is the average velocity.
Velocity is represented graphically by an what?
Velocity is represented graphically by a slope on a position-time graph. The steeper the slope, the greater the velocity.
Velocity is represented graphically by what?
Velocity is the slope of the line on a D-t graph
How is acceleration represented on a graph?
Acceleration is represented on a graph by the slope of the velocity-time graph. A positive slope indicates acceleration in the positive direction, while a negative slope indicates acceleration in the negative direction. A horizontal line on the graph represents constant velocity, with zero acceleration.
Which physical quantity is given by slope of v-t graph?
The physical quantity given by the slope of a velocity-time graph is acceleration. This is because the slope represents the rate of change of velocity over time, which is how acceleration is defined (acceleration = change in velocity / time taken).
Is The slope on a position-time graph is representative of the acceleration of the object?
No, the slope on a position-time graph represents the object's velocity, not acceleration. Acceleration would be represented by the slope of the velocity-time graph.
Does the slope of a position time graph represent average velocity or rate of change of velocity?
The slope of a position-time graph represents the average velocity of an object. It does not represent the rate of change of velocity, which would be represented by the slope of a velocity-time graph.
How is deceleration represented on a velocity or time graph?
a negative slope this is for my e2020 home boyz
Is velocity the slope of the displacement vs time graph true or false?
True. Velocity is the rate of change of displacement with respect to time, which is represented by the slope of the displacement versus time graph.
How is deceleration represented on a velocity per time graph?
It is radial the velocity in a direction towards or away from a fixed point of reference (the origin) at a given time. The velocity time graph takes no account of motion in a direction across the radial direction.
Does the slope of a speed-versus-time graph represents acceleration?
No, the slope of a speed-versus-time graph represents the rate of change of speed, not acceleration. Acceleration is represented by the slope of a velocity-versus-time graph.
The slope of velocity versus time graph gives?
The slope of a velocity versus time graph gives acceleration. By calculating the slope of the graph at a particular point, you can determine the acceleration of an object at that specific moment in time.
If the velocity is constant describe the slope of the graph on a position vs. time graph.?
If velocity is constant, the slope of the graph on a position vs. time graph will be a straight line. The slope of this line will represent the constant velocity of the object.
