The radial velocity ie velocity towards or away from your starting point. It is NOT the ordinary speed or velocity because you can run in a circle around your starting point at top speed but the distance will not change so the slope of the distance time graph will be zero.
If an x-t graph is a position-time graph, velocity is the slope of the line on the graph.
if there is a slope, the velocity is either increasing or decreasing. This is acceleration.
It is the average velocity.
The slope of the speed/time graph is the magnitude of acceleration. (It's very difficult to draw a graph of velocity, unless the direction is constant.)
By an arrow, a vector. Velocity is a vector quantity that must have both magnitude (speed) and direction (bearing).
Velocity is the slope of the line on a D-t graph
Acceleration is represented on a graph by the slope of the velocity-time graph. A positive slope indicates acceleration in the positive direction, while a negative slope indicates acceleration in the negative direction. A horizontal line on the graph represents constant velocity, with zero acceleration.
The physical quantity given by the slope of a velocity-time graph is acceleration. This is because the slope represents the rate of change of velocity over time, which is how acceleration is defined (acceleration = change in velocity / time taken).
No, the slope on a position-time graph represents the object's velocity, not acceleration. Acceleration would be represented by the slope of the velocity-time graph.
a negative slope this is for my e2020 home boyz
The tangent at a point on the position-time graph represents the instantaneous velocity. 1. The tangent is the instantaneous slope. 2. Rather than "average" velocity, the slope gives you "instantaneous" velocity. The average of the instantaneous gives you average velocity.
True. Velocity is the rate of change of displacement with respect to time, which is represented by the slope of the displacement versus time graph.
It is radial the velocity in a direction towards or away from a fixed point of reference (the origin) at a given time. The velocity time graph takes no account of motion in a direction across the radial direction.
No, the slope of a speed-versus-time graph represents the rate of change of speed, not acceleration. Acceleration is represented by the slope of a velocity-versus-time graph.
If velocity is constant, the slope of the graph on a position vs. time graph will be a straight line. The slope of this line will represent the constant velocity of the object.
If your graph shows velocity on the vertical axis and time on the horizontal axis, then the slope of the graph represents the acceleration. More specifically, the slope of the graph at a specific point represents the acceleration at that instantaneous point in time. So if the slope of the graph doesn't change (i.e. the graph is a straight line), then the acceleration is constant and doesn't change over time. In calculus, this is represented as the derivative: The derivative of velocity with respect to time equals the acceleration.