0.15 kilometres.
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150 metres = approx 492 feet.
150 metres is just over 492 feet, therefore 49 x 10 feetin 150 metres.
9km per 60 minutes (1 hour) 9000m (9km) divided by 60 minutes (1 hour) is 150m per minute 150m (per minute) x 15 minutes = 2250m per 15 minutes That gives you 2250m (2.25km) per 15 minutes at 9 km per hour :) +++ Another approach there would have been to use the simple fraction of the hour: just divide 9000metres by 4. (I.e. multiply the distance by the number of hours.) However the you way you used is important by showing the principles of such calculations.
The volume does not provide enough information. First, there is nothing in the question to indicate whether the room is cuboid in shape or cylindrical. Furthermore, even if the room were cuboid, or it could be in the form of a cube or a very long narrow tunnel (with a rectangular cross section).
To totally cross the bridge the train must travel (850m + 150m) 1 km. 1 km in 100 seconds is 10 m/s roughly 20 mph, so the answer is yes, with ease.