distance = velocity x time = 15 m/s x 4 s = 60 m
The average of 6, 15 and m is (6 + 15 + m) / 3 = (21 + m)/3 = 7 + m/3
Assuming that "m" is your variable: π = 15*m Divide by 15 π/15 = m Reverse equation (reflexive property) m = π/15
15
Use this equation.... x= x0 + V0*t + a*t^2 x0 = 0 v0 = 75 m/s a = (145-75)/15 = 4.67 m/s^2 t = 15 s x = 0 + 75 m/s * 15s + 4.67 m/s^2 *15^2 x = 2176 m
25 meters in 15 minutes.
15*cos(60) = 7.5 7.5 m
m-15=3 m-15+15=3+15 m=3+15 m=18
distance = velocity x time = 15 m/s x 4 s = 60 m
very very far off Nucleus is of the order of fermi (10-15 m.).And atom is of the order of angstorm A (10-10 m.).Now you realise
15= M on a D M C
How far will a car travel in 15 min at 20 m/s ?
The average of 6, 15 and m is (6 + 15 + m) / 3 = (21 + m)/3 = 7 + m/3
If it accelerates from 75 m/s to 145 m/s at a uniform rate, then its average speed duringthe acceleration is 0.5(145+75) = 110 m/s.Distance covered in 15 sec at average speed of 110 m/s = (15 x 110) = 1,650 m = 1.65 km.
15 m x 1,000 m = 15,000 m2
105
Assuming that "m" is your variable: π = 15*m Divide by 15 π/15 = m Reverse equation (reflexive property) m = π/15