2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
-- Add 5p to each side of the equation. -- Add 15 to each side of the equation. -- Look at the equation and find the one last step that will give you " p = a number ", which is the solution.
5p - 3 = 15Add 3 to each side:5p = 18Divide each side by 5:p = 18/5 = 3.6
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
-3
15
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5
Solve the following equation for A : 2A/3 = 8 + 4A
3.5
x + 5 = 4x/3 Solve for x multiply both sides of the equation by 3... 3 * (x + 5) = 3 * (4x/3) 3x + 15 = 4x subtract 3x from both sides of the equation (3x + 15) - 3x = (4x) - 3x 15 = x x = 15
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
12/3 = 4
Add 5 to both sides of the equation to get rid of the - 5. -3x - 5 + 5 = -20 + 5 Solve and simplify. -3x = -15 Divide both sides of the equation by -3. x = 5
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
You cannot solve one linear equation with two variables.
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".