Assuming what you're asking is for the circumference (distance around the entire wheel) the formula is r*2*pi.
In this case the circumference is roughly 157 inches.
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If by "27 inch wheel" you mean:"a wheel with a circumference of 27 inches" The answer is 27 inches."a wheel with a radius of 27 inches" The answer is 54π inches"a wheel with a diameter of 27 inches" The answer is 27π inches
If it doesn't slip, it travels one circumference of the rim with each rotation.The circumference = (2 pi) times (the radius) = (2 pi) x (14.75) = 92.677 inches. (rounded)
28inch is diameter as far as I'm aware. 28/2 is 14in radius.
Generally squares are not thought of as having a radius, but you could as what is the range of distances from the center of the shape to the outside of the shape. The closest point would be tha median point on the longer side, which would be at a distance of 1/2 the length of the shorter side. The shorter side is two inches in length, so that minimum "radius" is one inch. The furthest point would be the hypotenuse to the far corner from the centre. Using the Pythagorean theorem, we can say that it at a distance of the square root of three squared plus 1 squared. So the longest distance is the square root of ten, or just over three inches.
A red hypergiant star could have a radius of up to 2000 solar radii or more, where one solar radius is the radius of our sun. If at the centre of our solarsystem, a hypergiant could extend out as far as Jupiter or more.